I could probably come up with a figure if I knew the weight of the counterbalancer. It likely isn't much, though. I want to say that a Blaster makes 15 lb.ft. torque, which equates to having 15lbs pushing down on a one foot bar at that is at 90°, or 30lbs pushing on a 6" bar, 60lbs on a 3"bar, etc.
This is a hypothetical set of numbers as I don't know the specifics for the counterbalancer, but you'll get the idea. When you reduce the weight of anything that rotates (in this case, a counterbalancer), you are reducing the rotational inertia. Inertia is the ability of an object to maintain it's current speed, whether it be 0mph or mach 4. If you take 1lb of material and add it to the outside of the lobes of the CB (I'm not typing counterbalancer anymore), it would have a higher rotational inertia than if you added it to the shaft.
Now this is where my math starts to become hazy as it's been quite some time since I've done all of this. If your CB lobes weigh 1lb each and the center of mass for each of them is at 1.5", they would require .25lb.ft. or torque to move. Also, you have to factor the weight of the CB shaft, the resistance of the bearings, the air resistance against the lobes, and the mechanical losses between the gears into the equation, although it would be much less significant. I wouldn't estimate more than .05lb.ft. loss there. Even then, you'd be only sitting at 15.3lb.ft. at peak.
So if the lobes weigh 1lb (total of 2lbs) and have a center mass that is 1.5" from the axis of rotation, you'd see a loss of about 1.6%.